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9x^2+30x+25=1
We move all terms to the left:
9x^2+30x+25-(1)=0
We add all the numbers together, and all the variables
9x^2+30x+24=0
a = 9; b = 30; c = +24;
Δ = b2-4ac
Δ = 302-4·9·24
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*9}=\frac{-36}{18} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*9}=\frac{-24}{18} =-1+1/3 $
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